Explain emission lines and absorption lines.

Vedclass pdf generator app on play store
Vedclass iOS app on app store
(N/A) $1$. Emission Lines: When an atom in an excited state transitions to a lower energy state,it emits a photon with energy equal to the difference between the two energy levels $(E_2 - E_1 = h\nu)$. This results in a bright line in the spectrum at a specific wavelength,known as an emission line.
$2$. Absorption Lines: When an atom in a lower energy state absorbs a photon of energy exactly equal to the difference between its current state and a higher energy state $(h\nu = E_2 - E_1)$,it transitions to the higher state. This removal of specific wavelengths from a continuous spectrum creates dark lines,known as absorption lines.

Explore More

Similar Questions

The energy of an electron in the first excited state of an $H$-atom is $-3.4 \ eV$. Its kinetic energy is ........ $eV$.

The ratio of the energies of the hydrogen atom in its first to second excited state is

As the $n$ (number of orbit) increases,the difference of energy between the consecutive energy levels

Energy of an electron in the second orbit of a hydrogen atom is $E_{2}$. The energy of an electron in the third orbit of $He^{+}$ will be

$A$ monochromatic light is incident on a hydrogen sample in the ground state. Hydrogen atoms absorb a fraction of light and subsequently emit radiation of six different wavelengths. The frequency of incident light is $x \times 10^{15} \ Hz$. The value of $x$ is (Given $h = 4.25 \times 10^{-15} \ eVs$)

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo